A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second. The deck is 32 feet above the ground.
The problem uses the equation h = -16t2+v0t+h0, where h is initial height and v is initial velocity.
h = -16t2+192t+32
The vertex of the parabola is 608, so that means that 608 feet is the highest point the cannonball will reach.
You use the quadratic formula to find out how high the cannon ball will go, or:
x=(-b±√(b^2-4ac))/2a
a = -16 b = 192 and c = 32
When you plug in these numbers, you get 12.16, or about 12 seconds long.
I like how you provide info on how you did your steps. Wish you had shown your work.
ReplyDeleteI agree with Tyler. Besides no work, good answers.
ReplyDeleteI like the way that you did that steps, but as said above showing the work would be nice
ReplyDelete